hyperalgebra
基本解释
- [數]超代數
英汉例句
- Garland constructs an integral form U_z in the universal enveloping algebra U(g(A))of affine Lie algebra g(A), and defines, for any field K, U_k=U_z(?) _zK to be the affine hyperalgebra of g(A).
Garland對倣射李代數g(A)的普遍包絡代數U(g(A))搆造了一個Z-形式U_Z,從而對任何域K,定義了g(A)的倣射超代數U_k([2])。